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Question : A triangle has a base of  \(25m\)  and its area is  \(375m^{2}\)  find its height?  Answer : Height of the right angle triangle is  \(30m\)  . Explanation : Given base is  \(25m\)  and area is  \(375m^{2}\) Figure-1 (right angle triangle) Now we know area of right angle triangle=  \(\frac{1}{2}\times base \times height\) So according to question,  \(\frac{1}{2}\times base \times height\) =375 \[\Rightarrow base \times height= 375 \times 2\] \[\Rightarrow 25 \times height= 750\] \[\Rightarrow height= \frac{750}{25}\] \[\Rightarrow height= 30\] Hence, height of the right angle triangle is \(30m\)  . (Answer)

Question Id: MA 0000002 Question :  The perimeter of a triangle is 36 cm if its sides are in the ratio of 1:3:2 find the all sides of the triangle ? Answer :  \(6cm\), \(18cm\) and \(12cm\) Explanation : Ratio of sides of triangle is given 1:3:2 Let, sides are \(x\), \(3x\) and \(2x\) Then perimeter will be, \(x+2x+3x=6x\) According to question perimeter is given 36cm. So  \(6x=36\) \[\Rightarrow x=\frac{36}{6}\] \[\Rightarrow x=6\] So,  now \(x=6\), \(3x=18\) and \(2x=12\) Hence, sides of the triangle are 6cm, 18cm and 12cm. (Answer)