Find the (a) maximum frequency (b) minimum wavelength of X-rays produced by 30 kV electrons.
Question Id: PH0000012 Question : Find the (a) maximum frequency (b) minimum wavelength of X-rays produced by 30 kV electrons. Answer : (a) Maximum frequency of the X-ray produced by 30kV electron is \(\ 7.253 \times 10^{18}Hz \). (b) Minumum wavelength ( \(\lambda\) ) is \(0.41 \) angstroms. Explanation : Given, potential \(V=30kV\) \(\Rightarrow V=30 \times 10^3V\) \(\Rightarrow V=3 \times 10^4V\) So, energy of the X-ray is \(E=3 \times 10^4eV\) [ \(1eV=1.602\times 10^{-19}J\) ] We know a particle having frequency ( \(\nu\) ) contain energy \(E=h\nu\) ; where h is Planck's constant \(h=6.626\times 10^{-34}Js\) \[\Rightarrow \nu =\frac{E}{h}\] \[\Rightarrow \nu =\frac{1.602\times 10^{-19} \times 3 \times 10^{4}}{6.626\times 10^{-34}}\] \[\Rightarrow \nu =\frac{1.602 \times 3\times 10^{19} }{6.626}\] \[\Rightarrow \nu =0.7253 \times ...